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mysql sum的用法

方法如下 写入语句:“select col1,sum(cols2) from table_name group by col1 having sum(col2)>100” 写入语句可以用where,having代表查询按照col1分组后,sum(col2)大于100。 SQL即结构化查询语言,是一种特殊目的的编程语言,是一种数据库查...

$sql = "SELECT SUM(COST) sum FROM LIST"; $res = mysql_query($sql); $row = mysql_fetch_assoc($res); echo $row['sum'];

如下: select col1,sum(cols2) from table_name group by col1 having sum(col2)>100 不需要用where,用having就可以,这个就代表查询按照col1分组后,sum(col2)大于100的那些。

你的求和方式是正确的,注意一下表名和字段的大小写

CREATE?TABLE?`a`?( `id`?mediumint(8)?unsigned?NOT?NULL?AUTO_INCREMENT,`fid`?smallint(6)?unsigned?NOT?NULL?DEFAULT?'0',`cnt`?smallint(6)?unsigned?NOT?NULL?DEFAULT?'0',... ... ... PRIMARY?KEY?(`id`), KEY?`idx_fid`?(`fid`), )?ENGI...

mysql保留字段小数点后两位小数 用函数:truncate(s.price,2)即可。 如果想用四舍五入的话用round(s.price,2)。

select sum(zong) from table where unix_timestamp(date) between unix_timestamp('2013-05-05') and unix_timestamp('2013-09-01') group by date;

先筛选出销售员A和B,然后按销售员分组汇总销售额就可以了。请参考下列SQL语句: select 销售员,sum(销售额) as 个人销售总额 from T where 销售员 in ('A','B') group by 销售员;

SELECT a.userid, a.mai, i.hua FROM (SELECT userid, SUM(number) AS mai FROM account WHERE state=1 GROUP BY userid) AS a, (SELECT userid, SUM(total) AS hua FROM info WHERE state=1 GROUP BY userid) AS i WHERE a.userid=i.userid AND...

select sum(B) where A='张三' and C='1'

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